Ok, the answer. Paradox (loop) destroyed on the second guess.
Firstly, the question has no room for negotiation therefore can only be interpreted one way. Sure, mistaken readers exist but that doesn’t change the grounds of the question. You must choose at random and you must suppose the answer.
Here’s a tip. To make it truly random, even though you know what answers are there, you can hypothetically cover the numbers up as if you don’t know what answers are there. Once you have then chosen an answer, now is a simple time to realise what the answer also should be.
4 answers, all unknown, 25% chance of being correct. Well, not quite. Of course, it depends what answers are given. using common denominators we can see there is only 3 possible answers. This “3” is where the 33.3% mistake comes from, for some people but if so, is actually both wrong and irrelevant. Look :
4 answers all showing 100%
2 answers showing 50% and 2 answers showing anything else
1 answer showing 25% and 3 answers showing anything else
Now uncover the answers. This removes any (some have referred to referential loop or schroedingers cat) paradox, before a second loop simply by working out exactly what the answers could be after guaranteeing a total random state. It’s not negotiable.
it is in fact simply a trick question obviously designed to get people thinking.